You must have wondered “How Admission Advice predict rank given only expected JEE Main marks and Board Percentage?” or “How Resonance predicted rank is close to the actual ranks?” Well the answer is simple. We follow the same methodology as followed by CBSE. Confused how can we do that? Let’s see how?
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HYou give us JEE Main expected marks. Let’s call it ‘x’. As illustration, let this x be 250.
- You give us Board Percentage. Let this percentage be 90.
Now, as we have a data of percentages of tens of thousands of students of 2014, we calculate your expected percentile score based on this data. For eg, if we have 10000 students data and student who got 90% has 9500 students below him, your percentile becomes 95. Remember this percentile is the most important one.
Now we also have JEE Main scores of tens of thousands of students. We do the following:
- Suppose we have 10000 students of whom we have JEE Mains marks of previous year. We arrange them in decreasing order and see the marks of a student who has 9500 students below him (seeing the same percentile score). We take the numbers of this student and call it “y”. In our example, let it be 100.
- Next, we repeat the above exercise but this time only with students having same board as you. For eg, we take all students of CBSE (if your board is CBSE) and arrange their JEE Mains marks. Next, we see the marks of a student who has 95% students below him. We take the numbers of this student and call it “z”. In our example, let it be 120.
As per CBSE guidelines, the normalized score becomes:
N = 0.6*x + 0.4*(y + z)/2
In our example with x = 250, y = 100 and z = 120, this value becomes
N = 172
This is the final score based on which your rank will be calculated. Guess what, we have the range for this data too. For example, If, in 2014, the rank corresponding to this score is 11500, we report 10001 to 12500.
Now that you know how do we predict your ranks, why don’t you give it a shot by clicking here?
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